Jenna Dewan Tatum Scheduled To Appear On July 21 “Tonight Show Starring Jimmy Fallon”

The “World Of Dance” host will visit NBC’s “Tonight Show Starring Jimmy Fallon.”

Jenna Dewan Tatum | Peter Kramer / NBC Universal

On the morning of July 21, Jenna Dewan Tatum will appear on “Live With Kelly & Ryan.”

That night, she will appear on “The Tonight Show Starring Jimmy Fallon.”

NBC confirms the “World Of Dance” host as an interview guest for the episode.

The July 21 “Tonight Show” will also feature appearances by Kevin Bacon and Nate Bargatze.

NBC’s official “Tonight Show” listings follow:

Friday, July 14: Guests include Kate McKinnon, John Cena and musical guest Mac DeMarco. OAD 6/9/17

Monday, July 17: Guests include Queen Latifah, Kyle Mooney and musical guest Portugal. The Man. Show 705

Tuesday, July 18: Guests include Jada Pinkett Smith, Dane DeHaan and musical guest Rita Ora. Dave Davies sits in with The Roots. Show 706

Wednesday, July 19: Guests include Harry Styles, Jenny Slate and musical guest The Who. Show 707

Thursday, July 20: Guests include Charlize Theron, Michael Phelps, Julie Klam and musical guest SZA. Show 708

Friday, July 21: Guests include Kevin Bacon, Jenna Dewan Tatum and Nate Bargatze. Show 709

Written by Brian Cantor

Brian Cantor is the editor-in-chief for Headline Planet. He has been a leading reporter in the music, movie, television and sporting spaces since 2002.

Brian's reporting has been cited by major websites like BuzzFeed, Billboard, the New Yorker and The Fader -- and shared by celebrities like Taylor Swift, Justin Bieber and Nicki Minaj.

Contact Brian at brian.cantor[at]


Leave a Reply

Your email address will not be published.


“Descendants 2” Stars To Perform On July 17 “Good Morning America”

Jay-Z’s “4:44” Dominates US Album Sales Race, Takes #1 On Billboard 200