Ever since James Holzhauer’s game-changing run on “Jeopardy” earlier this year, fans have been clamoring for a “greatest of all time” showdown with Holzhauer, Ken Jennings and Brad Rutter.<\/p>\n
This January, they will get their wish.<\/p>\n
ABC today announced plans for a primetime “Jeopardy” tournament fittingly titled “Jeopardy! The Greatest Of All-Time.” Holzhauer, Jennings and Rutter will compete in a series of matches; the first to win three will be crowned the GOAT and receive $1 million. The runners-up will each receive $250,000.<\/p>\n
The competition will begin on Tuesday, January 7, 2020 from 8-9PM ET. Additional episodes will air on January 8 and January 9; if needed, the competition will spill into Tuesday, Wednesday and Thursday of the following week.<\/p>\n
Iconic “Jeopardy” host Alex Trebek will perform that duty during the tournament.<\/p>\n
Arguably the most famous “Jeopardy” contestant, Jennings boasts the record for longest win streak (74 games). In addition to holding the most total winnings ($4.7 million), Rutter has never lost to a human opponent. Thanks to his inventive style of play, Holzhauer boasts the 15 greatest single-day winnings.<\/p>\n","protected":false},"excerpt":{"rendered":"The three most successful “Jeopardy” players ever will compete.","protected":false},"author":1,"featured_media":134780,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0},"categories":[1048],"tags":[233,13136,13135,9840,13137],"adace-sponsor":[],"yoast_head":"\n